Dataset of surface reactions for gwb programs Dataset format: sep22 Surface type: Gibbsite Model type: two-layer Surface potential: variable (specify a value in mV to set a constant potential model) Surface capacitance: variable (specify a value in F/m2 to set a constant capacitance model) Thermo dataset: thermo_minteq.tdat * * * Reaction dataset for sorption to Gibbsite, according to the two-layer model. * * Based on data of Karamalidis and Dzombak (2010), entered by Brian Farrell, May 2021. * * Dataset "Gibbsite_minteq.sdat" * * This dataset contains the K&D compilation, formatted for use with * "thermo_minteq.tdat", and expanded to include surface complexation reactions * for which binding constants have only been estimated (see K&D, 2010, * Chapter 8). * * Reference: Karamalidis, A.K. and D.A. Dzombak, 2010, Surface Complexation * Modeling: Gibbsite. Wiley, New York, 294 p. * * Unless otherwise stated, the reported uncertainty in log K values (see comments to * individual reactions) correspond to 95% confidence limits. -end- 1 basis species >AlOH charge= 0 mole wt.= 43.9888 g 3 elements in species 1.000 Al 1.000 H 1.000 O -end- 1 sorbing minerals Gibbsite (C) surface area= 32.0000 m2/g 1 sorption sites >AlOH site density= 8.0000 sites/nm2 * 5. Surface Properties of Gibbsite -end- 66 surface species >AlOH2+ charge= 1 mole wt.= 44.9967 g 2 species in reaction 1.000 >AlOH 1.000 H+ log K a= -7.1700 b= 0.0 * Table 5.7 * >AlOH2+ = >AlOH + H+ * pKa1 int = 7.17+-0.19, log Ka1 = -7.17 * * PPZC = .5 (pKa1 int + pKa2 int) = 9.17 >AlO- charge= -1 mole wt.= 42.9809 g 2 species in reaction 1.000 >AlOH -1.000 H+ log K a= 11.1800 b= 0.0 * Table 5.7 * >AlOH = >AlO- + H+ * pKa2 int = 11.18+-0.22, log Ka2 = -11.18 * Reaction reversed and log K value negated * * PPZC = .5 (pKa1 int + pKa2 int) = 9.17 >AlOCu+ charge= 1 mole wt.= 106.5269 g 3 species in reaction 1.000 >AlOH 1.000 Cu++ -1.000 H+ log K a= -.2500 b= 0.0 * Table 6.8 * log K1 int = 0.25+-0.08, value negated >AlOPb+ charge= 1 mole wt.= 250.1708 g 3 species in reaction 1.000 >AlOH 1.000 Pb++ -1.000 H+ log K a= -.3700 b= 0.0 * Table 6.12 * log K1 int = 0.37+-0.03, value negated >AlOCo+ charge= 1 mole wt.= 101.9141 g 3 species in reaction 1.000 >AlOH 1.000 Co++ -1.000 H+ log K a= 2.5200 b= 0.0 * Table 6.17 * log K1 int = -2.52+-0.05, value negated >AlOCd+ charge= 1 mole wt.= 155.3803 g 3 species in reaction 1.000 >AlOH 1.000 Cd++ -1.000 H+ log K a= 2.7300 b= 0.0 * Table 6.22 * log K1 int = -2.73+-0.08, value negated >AlOMn+ charge= 1 mole wt.= 97.9189 g 3 species in reaction 1.000 >AlOH 1.000 Mn++ -1.000 H+ log K a= 5.4900 b= 0.0 * Table 6.26 * log K1 int = -5.49+-?, value negated >AlOFe+ charge= 1 mole wt.= 98.8279 g 3 species in reaction 1.000 >AlOH 1.000 Fe++ -1.000 H+ log K a= 3.7700 b= 0.0 * Table 6.30 * log K1 int = -3.77+-?, value negated >AlOCa+ charge= 1 mole wt.= 83.0609 g 3 species in reaction 1.000 >AlOH 1.000 Ca++ -1.000 H+ log K a= 10.4900 b= 0.0 * Table 6.35 * log K1 int = -10.49+-?, value negated >AlOZn+ charge= 1 mole wt.= 108.3508 g 3 species in reaction 1.000 >AlOH 1.000 Zn++ -1.000 H+ log K a= .9600 b= 0.0 * Table 6.40 * log K1 int = -0.96+-0.2, value negated >AlOHg+ charge= 1 mole wt.= 243.5709 g 4 species in reaction 1.000 >AlOH 1.000 Hg(OH)2 1.000 H+ -2.000 H2O log K a= -9.3400 b= 0.0 * Table 6.45 * log K1 int = 9.34+-0.14, value negated * * Note, reaction in Table 6.43 is not properly balanced. * An extra H2O was added here. >AlOH-HgOHCl charge= 0 mole wt.= 297.0391 g 5 species in reaction 1.000 >AlOH 1.000 Hg(OH)2 1.000 H+ 1.000 Cl- -1.000 H2O log K a= -14.4000 b= 0.0 * Table 6.45 * log K2 int = 14.40+-2.46, value negated >AlOUO2+ charge= 1 mole wt.= 313.0087 g 3 species in reaction 1.000 >AlOH 1.000 UO2++ -1.000 H+ log K a= -1.2200 b= 0.0 * Table 6.50 * log K1 int = 1.22+-0.17, value negated >AlOUO2(OH)3-- charge= -2 mole wt.= 364.0306 g 4 species in reaction 1.000 >AlOH 1.000 UO2++ 3.000 H2O -4.000 H+ log K a= 22.0000 b= 0.0 * Table 6.50 * log K3 int = -22.0+-0.01, value negated >AlO(UO2)3(OH)5 charge= 0 mole wt.= 938.1008 g 4 species in reaction 1.000 >AlOH 3.000 UO2++ 5.000 H2O -6.000 H+ log K a= 15.6200 b= 0.0 * Table 6.50 * log K4 int = -15.62+-1.40, value negated >AlOTh+++ charge= 3 mole wt.= 275.0209 g 3 species in reaction 1.000 >AlOH 1.000 Th++++ -1.000 H+ log K a= -10.8300 b= 0.0 * Table 6.55 * log K1 int = 10.83+-0.24, value negated >AlOTh(OH)++ charge= 2 mole wt.= 292.0282 g 4 species in reaction 1.000 >AlOH 1.000 Th++++ 1.000 H2O -2.000 H+ log K a= -3.4000 b= 0.0 * Table 6.55 * log K2 int = 3.40+-0.18, value negated >AlH2PO4 charge= 0 mole wt.= 123.9687 g 4 species in reaction 1.000 >AlOH 1.000 PO4--- 3.000 H+ -1.000 H2O log K a= -26.3100 b= 0.0 * Table 7.8 * log K1 int = 26.89+-0.14, value negated >AlHPO4- charge= -1 mole wt.= 122.9608 g 4 species in reaction 1.000 >AlOH 1.000 PO4--- 2.000 H+ -1.000 H2O log K a= -19.4800 b= 0.0 * Table 7.8 * log K2 int = 19.37+-?, value negated >AlPO4-- charge= -2 mole wt.= 121.9529 g 4 species in reaction 1.000 >AlOH 1.000 PO4--- 1.000 H+ -1.000 H2O log K a= -13.5700 b= 0.0 * Table 7.8 * log K3 int = 13.57+-0.94, value negated >AlH2AsO4 charge= 0 mole wt.= 167.9165 g 4 species in reaction 1.000 >AlOH 1.000 AsO4--- 3.000 H+ -1.000 H2O log K a= -26.2600 b= 0.0 * Table 7.13 * log K1 int = 26.26+-?, value negated >AlHAsO4- charge= -1 mole wt.= 166.9086 g 4 species in reaction 1.000 >AlOH 1.000 AsO4--- 2.000 H+ -1.000 H2O log K a= -21.7900 b= 0.0 * Table 7.13 * log K2 int = 21.79+-0.54, value negated >AlOHAsO4--- charge= -3 mole wt.= 182.9080 g 2 species in reaction 1.000 >AlOH 1.000 AsO4--- log K a= -6.3900 b= 0.0 * Table 7.13 * log K4 int = 6.39+-0.39, value negated >AlH2AsO3 charge= 0 mole wt.= 151.9171 g 3 species in reaction 1.000 >AlOH 1.000 H3AsO3 -1.000 H2O log K a= -1.7800 b= 0.0 * Table 7.18 * log K1 int = 1.78+-0.05, value negated >AlHMoO4 charge= 0 mole wt.= 187.9270 g 4 species in reaction 1.000 >AlOH 1.000 MoO4-- 2.000 H+ -1.000 H2O log K a= -14.7700 b= 0.0 * Table 7.23 * log K1 int = 14.77+-3.83, value negated >AlMoO4- charge= -1 mole wt.= 186.9191 g 4 species in reaction 1.000 >AlOH 1.000 MoO4-- 1.000 H+ -1.000 H2O log K a= -3.7200 b= 0.0 * Table 7.23 * log K2 int = 3.72+-0.9, value negated >AlOHMoO4-- charge= -2 mole wt.= 203.9264 g 2 species in reaction 1.000 >AlOH 1.000 MoO4-- log K a= -1.8700 b= 0.0 * Table 7.23 * log K3 int = 1.87+-0.72, value negated >AlOHSeO4-- charge= -2 mole wt.= 186.9464 g 2 species in reaction 1.000 >AlOH 1.000 SeO4-- log K a= -4.5300 b= 0.0 * Table 7.28 * log K3 int = 4.53+-?, value negated >AlHCrO4 charge= 0 mole wt.= 143.9830 g 4 species in reaction 1.000 >AlOH 1.000 CrO4-- 2.000 H+ -1.000 H2O log K a= -13.4000 b= 0.0 * Table 7.33 * log K1 int = 13.40+-?, value negated >AlCrO4- charge= -1 mole wt.= 142.9751 g 4 species in reaction 1.000 >AlOH 1.000 CrO4-- 1.000 H+ -1.000 H2O log K a= -9.5000 b= 0.0 * Table 7.33 * log K2 int = 9.50+-?, value negated >AlH2BO3 charge= 0 mole wt.= 87.8055 g 3 species in reaction 1.000 >AlOH 1.000 H3BO3 -1.000 H2O log K a= -1.5700 b= 0.0 * Table 7.36 * log K1 int = 1.57+-?, value negated >AlH3BO4- charge= -1 mole wt.= 104.8128 g 3 species in reaction 1.000 >AlOH 1.000 H3BO3 -1.000 H+ log K a= 7.6300 b= 0.0 * Table 7.38 * log K2 int = -7.63+-?, value negated >AlSO4- charge= -1 mole wt.= 123.0431 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 SO4-- 1.000 H+ log K a= .4500 b= 0.0 * Table 7.43 * log K2 int = -0.45+-?, value negated >AlOHSO4-- charge= -2 mole wt.= 140.0504 g 2 species in reaction 1.000 >AlOH 1.000 SO4-- log K a= -1.1900 b= 0.0 * Table 7.43 * log K3 int = 1.19+-0.73, value negated >AlF charge= 0 mole wt.= 45.9799 g 4 species in reaction 1.000 >AlOH 1.000 F- 1.000 H+ -1.000 H2O log K a= -8.7800 b= 0.0 * Table 7.48 * log K1 int = 8.78+-?, value negated >AlOHF- charge= -1 mole wt.= 62.9872 g 2 species in reaction 1.000 >AlOH 1.000 F- log K a= -2.8800 b= 0.0 * Table 7.48 * log K2 int = 2.88+-?, value negated >AlF2- charge= -1 mole wt.= 64.9783 g 4 species in reaction 1.000 >AlOH 2.000 F- 1.000 H+ -1.000 H2O log K a= -11.9400 b= 0.0 * Table 7.48 * log K3 int = 11.94+-?, value negated >AlOH4SiO4- charge= -1 mole wt.= 139.0956 g 3 species in reaction 1.000 >AlOH -1.000 H+ 1.000 H4SiO4 log K a= 4.1600 b= 0.0 * Table 7.53 * log K2 int = -4.16+-?, value negated >AlOBa+ charge= 1 mole wt.= 180.3209 g 3 species in reaction 1.000 >AlOH 1.000 Ba++ -1.000 H+ log K a= 8.5000 b= 0.0 * Table 8.2 * log K1 int = -8.5, value negated * Estimated using LFER in Fig. 8.1 >AlOSr+ charge= 1 mole wt.= 130.6009 g 3 species in reaction 1.000 >AlOH 1.000 Sr++ -1.000 H+ log K a= 8.2600 b= 0.0 * Table 8.2 * log K1 int = -8.26, value negated * Estimated using LFER in Fig. 8.1 >AlOMg+ charge= 1 mole wt.= 67.2929 g 3 species in reaction 1.000 >AlOH 1.000 Mg++ -1.000 H+ log K a= 5.9300 b= 0.0 * Table 8.2 * log K1 int = -5.93, value negated * Estimated using LFER in Fig. 8.1 >AlOAg charge= 0 mole wt.= 150.8489 g 3 species in reaction 1.000 >AlOH 1.000 Ag+ -1.000 H+ log K a= 6.7000 b= 0.0 * Table 8.2 * log K1 int = -6.70, value negated * Estimated using LFER in Fig. 8.1 >AlONi+ charge= 1 mole wt.= 101.6909 g 3 species in reaction 1.000 >AlOH 1.000 Ni++ -1.000 H+ log K a= 3.9200 b= 0.0 * Table 8.2 * log K1 int = -3.92, value negated * Estimated using LFER in Fig. 8.1 >AlOPuO2+ charge= 1 mole wt.= 318.9797 g 3 species in reaction 1.000 >AlOH 1.000 PuO2++ -1.000 H+ log K a= -2.3100 b= 0.0 * Table 8.2 * log K1 int = 2.31, value negated * Estimated using LFER in Fig. 8.1 >AlOSn+ charge= 1 mole wt.= 161.6709 g 3 species in reaction 1.000 >AlOH 1.000 Sn++ -1.000 H+ log K a= -4.6900 b= 0.0 * Table 8.2 * log K1 int = 4.69, value negated * Estimated using LFER in Fig. 8.1 >AlOPd+ charge= 1 mole wt.= 149.4009 g 3 species in reaction 1.000 >AlOH 1.000 Pd++ -1.000 H+ log K a= -5.5000 b= 0.0 * Table 8.2 * log K1 int = 5.50, value negated * Estimated using LFER in Fig. 8.1 >AlHCO3 charge= 0 mole wt.= 87.9986 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 CO3-- 2.000 H+ log K a= -21.4800 b= 0.0 * Table 8.7 * log K1 int = 21.48, value negated * Estimated using LFER in Fig. 8.3 >AlCO3- charge= -1 mole wt.= 86.9907 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 CO3-- 1.000 H+ log K a= -15.9300 b= 0.0 * Table 8.7 * log K2 int = 15.93, value negated * Estimated using LFER in Fig. 8.4 >AlHSO3 charge= 0 mole wt.= 108.0516 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 SO3-- 2.000 H+ log K a= -20.0700 b= 0.0 * Table 8.7 * log K1 int = 20.07 value negated * Estimated using LFER in Fig. 8.3 >AlSO3- charge= -1 mole wt.= 107.0437 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 SO3-- 1.000 H+ log K a= -13.5000 b= 0.0 * Table 8.7 * log K2 int = 13.50, value negated * Estimated using LFER in Fig. 8.4 >AlHSeO3 charge= 0 mole wt.= 154.9476 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 SeO3-- 2.000 H+ log K a= -19.4400 b= 0.0 * Table 8.7 * log K1 int = 19.44, value negated * Estimated using LFER in Fig. 8.3 >AlSeO3- charge= -1 mole wt.= 153.9397 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 SeO3-- 1.000 H+ log K a= -12.4000 b= 0.0 * Table 8.7 * log K2 int = 12.40, value negated * Estimated using LFER in Fig. 8.4 >AlHS2O3 charge= 0 mole wt.= 140.1156 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 S2O3-- 2.000 H+ log K a= -11.9400 b= 0.0 * Table 8.7 * log K1 int = 11.94, value negated * Estimated using LFER in Fig. 8.3 >AlS2O3- charge= -1 mole wt.= 139.1077 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 S2O3-- 1.000 H+ log K a= .5500 b= 0.0 * Table 8.7 * log K2 int = -0.55, value negated * Estimated using LFER in Fig. 8.4 >AlHWO4 charge= 0 mole wt.= 275.8370 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 WO4-- 2.000 H+ log K a= -14.1500 b= 0.0 * Table 8.7 * log K1 int = 14.15, value negated * Estimated using LFER in Fig. 8.3 >AlWO4- charge= -1 mole wt.= 274.8291 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 WO4-- 1.000 H+ log K a= -3.2600 b= 0.0 * Table 8.7 * log K2 int = 3.26, value negated * Estimated using LFER in Fig. 8.4 >AlH2VO4 charge= 0 mole wt.= 143.9364 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 VO4--- 3.000 H+ log K a= -28.5200 b= 0.0 * Table 8.7 * log K1 int = 28.52, value negated * Estimated using LFER in Fig. 8.3 >AlHVO4- charge= -1 mole wt.= 142.9285 g 4 species in reaction -1.000 H2O 1.000 >AlOH 1.000 VO4--- 2.000 H+ log K a= -23.4100 b= 0.0 * Table 8.7 * log K2 int = 23.41, value negated * Estimated using LFER in Fig. 8.4 >AlOH2SbO(OH)4 charge= 0 mole wt.= 250.7753 g 4 species in reaction 1.000 >AlOH 1.000 Sb(OH)6- 1.000 H+ -1.000 H2O log K a= -13.1600 b= 0.0 * Table 8.7 * log K1 int = 13.16, value negated * Estimated using LFER in Fig. 8.3 * * Note, thermo_minteq.tdat does not contain species SbO(OH)4-, * so reaction written assuming Sb(OH)6- is equivalent, using * log K = 0 for reaction Sb(OH)4- + H2O = Sb(OH)6-. * * >AlOH2SbO(OH)4 = >AlOH + SbO(OH)4- + H+ * log K = -13.16 * * Sb(OH)4- + H2O = Sb(OH)6- * log K = 0 * * >AlOH2SbO(OH)4 + H2O = >AlOH + Sb(OH)6- + H+ * log K = -13.16 >AlOHSbO(OH)4- charge= -1 mole wt.= 249.7674 g 3 species in reaction 1.000 >AlOH 1.000 Sb(OH)6- -1.000 H2O log K a= -1.5600 b= 0.0 * Table 8.7 * log K2 int = 1.56, value negated * Estimated using LFER in Fig. 8.4 * * Note, thermo_minteq.tdat does not contain species SbO(OH)4-, * so reaction written assuming Sb(OH)6- is equivalent, using * log K = 0 for reaction Sb(OH)4- + H2O = Sb(OH)6-. * * >AlOHSbO(OH)4- = >AlOH + SbO(OH)4- * log K = -1.56 * * Sb(OH)4- + H2O = Sb(OH)6- * log K = 0 * * >AlOHSbO(OH)4- + H2O = >AlOH + Sb(OH)6- * log K = -1.56 >AlOH2CNO charge= 0 mole wt.= 87.0138 g 3 species in reaction 1.000 >AlOH 1.000 OCN- 1.000 H+ log K a= -13.9900 b= 0.0 * Table 8.7 * log K1 int = 13.99, value negated * Estimated using LFER in Fig. 8.3 >AlOHCNO- charge= -1 mole wt.= 86.0059 g 2 species in reaction 1.000 >AlOH 1.000 OCN- log K a= -3.0000 b= 0.0 * Table 8.7 * log K2 int = 3.00, value negated * Estimated using LFER in Fig. 8.4 >AlOH2CN charge= 0 mole wt.= 71.0144 g 3 species in reaction 1.000 >AlOH 1.000 CN- 1.000 H+ log K a= -20.2600 b= 0.0 * Table 8.7 * log K1 int = 20.26, value negated * Estimated using LFER in Fig. 8.3 >AlOHCN- charge= -1 mole wt.= 70.0065 g 2 species in reaction 1.000 >AlOH 1.000 CN- log K a= -13.8200 b= 0.0 * Table 8.7 * log K2 int = 13.82, value negated * Estimated using LFER in Fig. 8.4 >AlOH2SCN charge= 0 mole wt.= 103.0784 g 3 species in reaction 1.000 >AlOH 1.000 SCN- 1.000 H+ log K a= -8.9900 b= 0.0 * Table 8.7 * log K1 int = 8.99, value negated * Estimated using LFER in Fig. 8.3 >AlOHSCN- charge= -1 mole wt.= 102.0705 g 2 species in reaction 1.000 >AlOH 1.000 SCN- log K a= 5.6500 b= 0.0 * Table 8.7 * log K2 int = -5.65, value negated * Estimated using LFER in Fig. 8.4 -end-